Introductio in analysin infinitorum

IN DEFINIEND. SUMMIS SERIER. INFINIT. 135 $S = \frac{1}{(n-m)^4} + \frac{1}{(n+m)^4} + \frac{1}{(3n-m)^4} + \frac{1}{(3n+m)^4} + \frac{1}{(5n-m)^4} + \&c.$ $T = \frac{1}{(n-m)^5} - \frac{1}{(n+m)^5} + \frac{1}{(3n-m)^5} - \frac{1}{(3n+m)^5} + \frac{1}{(5n-m)^5} - \&c.$ $V = \frac{1}{(n-m)^6} + \frac{1}{(n+m)^6} + \frac{1}{(3n-m)^6} + \frac{1}{(3n+m)^6} + \frac{1}{(5n-m)^6} + \&c.$ &c. Posito autem tang. $\frac{m\pi}{2n} = k$ erit, uti ostendimus, $P = A = \frac{k\pi}{2n} = \frac{k\pi}{2n}$ $Q = \frac{(k^2+1)\pi^2}{4n^2} = \frac{(2k^2+2)\pi^2}{2 \cdot 4 n [TRUNCATED]