Steps / Historical AI

Leonhard Euler · 1748 · Internet Archive

Introductio in analysin infinitorum

All 320 leaves · leaf 211

Transcription

RECURRENTIBUS. 183 $\frac{a-2apz\cos\Phi+appzz}{(1-2pz\cos\Phi+ppzz)^2}$ ortae terminus generalis est = $\frac{a\sin(n+1)\Phi}{\sin\Phi} p^n z^n$. Addantur hae fractiones invicem, ac ponatur $a+f=A$; $2a\cos\Phi+2f\cos\Phi-2g\sin\Phi=B$ & $a+f\cos2\Phi-g\sin2\Phi=0$, hinc erit $g=\frac{B+2A\cos\Phi}{2\sin\Phi}$, $a=\frac{A+B\cos\Phi}{1-\cos2\Phi}=\frac{A+B\cos\Phi}{2(\sin\Phi)^2}$ & $f=\frac{A\cos2\Phi-B\cos\Phi}{2(\sin\Phi)^2}$, & $g=\frac{B\sin\Phi+A\sin2\Phi}{2(\sin\Phi)^2}$. Hanc ob rem Seriei ex hac fractione $\frac{A+Bpz}{(1-2pz\cos\Phi+ppzz)^2}$, ortae terminus generalis est $\frac{A+B\cos\Phi}{2(\sin\Phi)^3}\sin(n+1)\Phi \cdot p^n z^n [TRUNCATED]
confidence 0.31 10 expressions source scan at the Internet Archive

This text was produced by machine and has not been corrected by hand. Where it matters, read the scan. Confidence is the model's own, not an external check.