Introductio in analysin infinitorum

EVOLUTIONE FACTORUM ORTIS. 237 CAP. XV. $S=(M-1)(1-\frac{1}{2^n}) - \frac{1}{9^n} - \frac{1}{15^n} - \frac{1}{21^n} - \frac{1}{25^n} - \frac{1}{27^n} - \&c.,$ & ob $M(1-\frac{1}{2^n}) = \frac{1}{3} + \frac{1}{3^n} + \frac{1}{9^n} + \frac{1}{15^n} + \frac{1}{21^n} + \&c.,$ erit $S=(M-1)(1-\frac{1}{2^n})(1-\frac{1}{3^n}) + \frac{1}{6^n} - \frac{1}{25^n} - \frac{1}{35^n} - \frac{1}{45^n} - \&c..$ Hinc, ob datam summam $M$, valor ipsius $S$ commode invenitur, si quidem $n$ fuerit numerus mediocriter magnus. 282. Inventis autem summis altiorum Potestatum, etiam summae Potestatum minorum ex formulis inventis exhiberi possunt. Atque hac methodo [TRUNCATED]