Introductio in analysin infinitorum

EVOLUTIONE FACTORUM ORTIS. 239 CAP. XV. fubtr. $\frac{1}{5^n} C = \frac{1}{5^n} + \frac{1}{25^n} + \frac{1}{35^n} + \frac{1}{55^n} + \&c.,$ erit $(1 - \frac{1}{5^n}) C = 1 + \frac{1}{7^n} + \frac{1}{11^n} + \frac{1}{13^n} + \frac{1}{17^n} + \&c.,$ sic sublati etiam funt omnes termini per $5$ divisibiles. Pari modo tolluntur termini divisibiles per $7$, $11$, reliquosque numeros primos; manifestum autem est sublatis omnibus terminis, qui per numeros primos divisibiles sint, solam unitatem relinqui. Quare pro $B$, $C$, $D$, $E$, \&c., valoribus restitutis tandem orietur $A(1 - \frac{1}{2^n})(1 - \frac{1}{3^n})(1 - \frac{1}{5^n})(1 - \frac{1}{7^n})(1 - \frac{1}{11^n})\&c. = 1,$ unde Seriei propositae summa erit = $A = [TRUNCATED]