Introductio in analysin infinitorum

EVOLUTIONE FACTORUM ORTIS. 249 CAP. XV. $C = (1 + \frac{1}{5^n})B = 1 + \frac{1}{7^n} - \frac{1}{11^n} + \frac{1}{13^n} - \frac{1}{17^n} + \frac{1}{19^n} - \frac{1}{23^n} \&c.$ $\frac{1}{7^n} C = \frac{1}{7^n} + \frac{1}{49^n} - \frac{1}{77^n} + \&c.$, subtrahatur, erit $D = (1 - \frac{1}{7^n})C = 1 - \frac{1}{11^n} + \frac{1}{13^n} - \frac{1}{17^n} + \frac{1}{19^n} - \&c.$ Ex his tandem fiet $A(1 + \frac{1}{2^n})(1 + \frac{1}{5^n})(1 - \frac{1}{7^n})(1 + \frac{1}{11^n})(1 - \frac{1}{13^n}) \&c. = 1$, ubi numeri primi unitate excedentes multipla senarii habent signum $-$, [TRUNCATED]