Introductio in analysin infinitorum

306 DE FRACTIONIBUS LIB. I. $\frac{1}{x} - m = \frac{mm}{n + \frac{(m+n)^2}{n + \frac{(m+2n)^2}{n + \frac{(m+3n)^2}{n + \&c.}}}}$ EXEMPLUM IV. Quoniam, supra §. 178., invenimus esse $\frac{\pi \text{ cof. } \frac{m\pi}{n}}{n \text{ fin. } \frac{m\pi}{n}} = \frac{1}{m} - \frac{1}{n-m} + \frac{1}{n+m} - \frac{1}{2n-m} + \frac{1}{2n+m} - \&c.,$ erit, pro fractione continuanda, $A=m$; $B=n-m$; $C=n+m$; $D=2n-m$; &c., unde fiet $\frac{\pi \text{ cof. } \frac{m\pi}{n}}{n \text{ fin. } \frac{m\pi}{n}} = \frac{1}{m} + \frac{mm}{n-2m + \frac{(n-m)^2}{2m + \frac{(n+m)^2}{n-2m + \frac{(2n-m)^2}{2m + \frac{( [TRUNCATED]