Introductio in analysin infinitorum

EX CIRCULO ORTIS. 95 Si ergo $n$ denotet numerum integrum quemcunque, erit CAP. VIII. $sin.(\frac{4n+1}{2}\pi+z) = +cos.z$ $sin.(\frac{4n+1}{2}\pi-z) = +cos.z$ $cos.(\frac{4n+1}{2}\pi+z) = -sin.z$ $cos.(\frac{4n+1}{2}\pi-z) = -sin.z$ $sin.(\frac{4n+2}{2}\pi+z) = -sin.z$ $sin.(\frac{4n+2}{2}\pi-z) = +sin.z$ $cos.(\frac{4n+2}{2}\pi+z) = -cos.z$ $cos.(\frac{4n+2}{2}\pi-z) = -cos.z$ $sin.(\frac{4n+3}{2}\pi+z) = -cos.z$ $sin.(\frac{4n+3}{2}\pi-z) = -cos.z$ $cos.(\frac{4n+3}{2}\pi+z) = +sin.z$ $cos.(\frac{4n+3}{2}\pi-z) = -sin.z$ $sin.(\frac{4n+4}{2}\pi+z) = [TRUNCATED]