Steps / Historical AI

Leonhard Euler · 1748 · Internet Archive

Introductio in analysin infinitorum

All 320 leaves · leaf 122

Transcription

94 DE QUANTITATIBUS TRANSCENDENT. LIB. I. tinentur. Erit autem porro $cof. z = fin. (\frac{1}{2}\pi - z)$, & $fin. z = cof. (\frac{1}{2}\pi - z)$, atque $(fin. z)^2 + (cof. z)^2 = 1$. Præter has denominationes notandæ sunt quoque hæ: tang. z, quæ denotat Tangentem Arcus z; cot. z Cotangentem Arcus z; constatque esse $tang. z = \frac{fin. z}{cof. z}$ & $cot. z = \frac{cof. z}{fin. z} = \frac{1}{tang. z}$; quæ omnia ex Trigonometria sunt nota. 128. Hinc vero etiam constat si habeantur duo Arcus y & z, fore $fin. (y+z) = fin. y. cof. z + cof. y. fin. z$, & $cof. (y+z) = cof. y. cof. z - fin. y. fin. z$, itemque $fin. (y-z) = fin. y. cof. z - cof. y. fin. z$ & $cof. (y-z) = cof. y. cof. z + fin. y. fin. z$. Hinc loco y substituendo Arcus $\frac{1}{2}\pi; \pi; \frac{3}{2}\pi, \&c.$, erit $fin. (\frac{1}{2}\pi + z) = + cof. z$ | $fin. (\frac{1}{2}\pi - z) = + cof. z$ $cof. (\frac{1}{2}\pi + z) = - fin. z$ | $cof. (\frac{1}{2}\pi - z) = + fin. z$ $fin. (\pi + z) = - fin. z$ | $fin. (\pi - z) = + fin. z$ $cof. (\pi + z) = - cof. z$ | $cof. (\pi - z) = - cof. z$ $fin. (\frac{3}{2}\pi + z) = - cof. z$ | $fin. (\frac{3}{2}\pi - z) = - cof. z$ $cof. (\frac{3}{2}\pi + z) = + fin. z$ | $cof. (\frac{3}{2}\pi - z) = - fin. z$ $fin. (2\pi + z) = + fin. z$ | $fin. (2\pi - z) = - fin. z$ $cof. (2\pi + z) = + cof. z$ | $cof. (2\pi - z) = + cof. z$ Si
confidence 0.36 26 expressions source scan at the Internet Archive

This text was produced by machine and has not been corrected by hand. Where it matters, read the scan. Confidence is the model's own, not an external check.