Leonhard Euler · 1748 · Internet Archive
Introductio in analysin infinitorum
All 320 leaves · leaf 287
Transcription
NUMERORUM. 259
$(1+x^2z)(1+x^3z)(1+x^4z) \&c. = \frac{Z}{1+xz}$ CAP. XVI.
ergo, posito $xz$ loco $z$, valor producti, qui erat $Z$, abibit in
$\frac{Z}{1+xz}$; sicque, cum fit
$Z = 1 + Pz + Qz^2 + Rz^3 + Sz^4 + \&c.$
erit
$\frac{Z}{1+xz} = 1 + Pxz + Qx^2z^2 + Rx^3z^3 + Sx^4z^4 + \&c.,$
multiplicetur ergo actu per $1+xz$, atque prodibit
$Z = 1 + Pxz + Qx^2z^2 + Rx^3z^3 + Sx^4z^4 + \&c.$
$+ xz + Px^2z^2 + Qx^3z^3 + Rx^4z^4 + \&c.,$
qui valor ipsius $Z$ cum superiori comparatus dabit
$P = \frac{x}{1-x}$; $Q = \frac{Px^2}{1-x^2}$; $R = \frac{Qx^3}{1-x^3}$; $S = \frac{Rx^4}{1-x^4}$ \&
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